SERC Recruitment 2021 Latest New Jobs vacancy

This Vacancy New updated on 26-April-2021

CSIR – SERC Tamil Nadu Jobs 2021. CSIR – SERC Recruitment Vacancies 2021 Apply For Technician – 7 Posts.

Who can Apply?

SSC/ 10th Class, ITI candidates may apply for the Jr Secretariat Asst, Driver, Technician job vacancies in SERC . The vacancies are in (Tamil Nadu) state govt. The recruitment offers great opportunity to apply for 10th 12th pass government jobs in (Tamil Nadu) state. Freshers may also apply.

What are the Current Vacancies in SERC ?

 

CSIR – SERC

 Jobs Career Notification Advt 2021-22 Latest

Apply For Technician – 7 Posts.

CSIR – SERC
Admit Card, Result, Exam, Application Form, Interview 2021-22

dekhogovtjobs.in

SERC Career Employment news notification is for the following job profiles: Jr Secretariat Asst, Driver, Technician .

SERC Recruitment 2021:Structural Engineering Research Centre Recruitment Selection Committee Tamil Nadu is going to invite online applications for Technician – 7 Posts in SERC Applicants who posses all the necessary educational qualifications and eligibility criteria may apply for the vacant posts.

Eligible candidates may apply to these posts by submitting their applications to the below given application address. Last date for submitting application is 31-05-2021.Selection of the eligible applicants to these posts will be made through Walkin Interview.

एसईआरसी भर्ती 2021: स्ट्रक्चरल इंजीनियरिंग रिसर्च सेंटर भर्ती चयन समिति तमिलनाडु तकनीशियन के लिए ऑनलाइन आवेदन आमंत्रित करने जा रही है – एसईआरसी आवेदकों में 7 पद जो सभी आवश्यक शैक्षणिक योग्यता और पात्रता मानदंड रखते हैं वे रिक्त पदों के लिए आवेदन कर सकते हैं।

योग्य उम्मीदवार नीचे दिए गए आवेदन पते पर अपने आवेदन जमा करके इन पदों पर आवेदन कर सकते हैं। आवेदन जमा करने की अंतिम तिथि 31-05-2021 है।

SERC Recruitment 2021 Job Notification Brief Information:

Organization Name:Structural Engineering Research Centre Recruitment Selection Committee
Number of Posts:07 Vacancies
Apply Mode:Online
Official Website:https://serc.res.in/
Job Location: Chennai
Job type:

Tamil Nadu

Govt Jobs

Start Application:26/04/2021
Last Date to Apply:31-05-2021

 

CSIR – SERC Technician – 7 Posts

S.No. Administrative Post Total Vacancy
1.Technician07

 

SERC requires Jobs 2021 Essential Qualification:

please Candidates are requested to check other education qualification details to the official website which is https://serc.res.in/

qualificationSSC/ 10th Class, ITI

 

SERC Age Limits:

Eligible candidates can apply for the job check the age limit details given below

age limit63 years

For more details the SERC official notification

SERC Selection:

  • Written exam

SERC Application Fees:

official notification

SERC Application Pay:

pay19900-63200

How to Apply For SERC ?

Candidates can apply online application using the website “https://serc.res.in/
” submitting online application.

  • Application Steps to Apply Online for SERC  Recruitment:
    Applying to Online Applicants have valid email & Scanned copies of photo, signature.
    Candidates go to official Website link  https://serc.res.in/
    Log in “Current Openings” & Select the desired Vacancy.
    Read the information carefully & Click on “Apply Online”.
    Click on “Click here for New Registration”, if you are a new user.
    Complete the Online Registration & Click on “Submit” batten.
    After Online Registration, Log in with Registered Number & Password.
    Fill the all details in the application & upload Photo, Signature.
    Take a print out of Online application for future use.
    Contact Address the application form:
  • CSIR Road, CSIR Campus, Chennai, Tamil Nadu 600113

SERC Notification 2021 & Apply Online

Deputy Commissioner, Narnaul Job Notification 2021:Official Job Notification pdf
SERC Online Recruitment Link:Apply Online

 

Check Also

ACTREC Recruitment 2021-2022 Latest New Jobs Vacancy

ACTREC Jobs 2021 Apply For Scientific Officer, Medical Physicist, Technician & Other – 20 Posts …

Leave a Reply

Your email address will not be published. Required fields are marked *

twelve − eleven =